4x^2=5x/3x-1

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Solution for 4x^2=5x/3x-1 equation: 


x in (-oo:+oo)

4*x^2 = ((5*x)/3)*x-1 // - ((5*x)/3)*x-1

4*x^2-(((5*x)/3)*x)+1 = 0

4*x^2+(-5/3)*x^2+1 = 0

7/3*x^2 = -1 // : 7/3

x^2 = -3/7

x belongs to the empty set

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